Luxury Escapes: The World's Best Holidays
TV

Luxury Escapes: The World's Best Holidays

August 29, 2023 3 Seasons 33 Episodes Returning Series

Overview

A showcase of the best holiday hotspots across Australia and the world, with luxurious hotels, great places to eat, drink and explore.

Seasons & Episodes

Season 1

Season 1

2023 12 Episodes

The World's Best Holidays showcases the most loved and desired hotspots in Australia and around the world. We visit some incredible hotels, we experience beautiful places to eat, drink and explore and we introduce you to people in the know.

Season 2

Season 2

2024 12 Episodes

Two travellers, two very different travel agendas, one luxury holiday. Pack your bags for a Luxury Escape like no other as some of Australia’s most loved personalities explore the world on hand-picked, five-star holidays.

Season 3

2025 9 Episodes

Key Information

Network LifeStyle
Type Documentary
Language EN
Country Australia

Cast & Crew

Cameron Daddo

Cameron Daddo

Self

Miguel Maestre

Miguel Maestre

Self

Molly Nicholson

Self

Jane Hall

Jane Hall

Self

Melissa Leong

Melissa Leong

Self

Holly Kingston

Self

Mike Reid

Mike Reid

Self

Pia Miranda

Pia Miranda

Self

Bernard Curry

Bernard Curry

Self

Rebecca Gibney

Rebecca Gibney

Self

Wendy Moore

Wendy Moore

Self

Neale Whitaker

Neale Whitaker

Self

Frequently Asked Questions

A showcase of the best holiday hotspots across Australia and the world, with luxurious hotels, great places to eat, drink and explore.

Luxury Escapes: The World's Best Holidays has 3 seasons with 33 episodes.

Luxury Escapes: The World's Best Holidays premiered on August 29, 2023.

Yes, Luxury Escapes: The World's Best Holidays is currently ongoing with new episodes.

Luxury Escapes: The World's Best Holidays originally aired on LifeStyle. Check your local streaming services for availability.

Luxury Escapes: The World's Best Holidays has a rating of 0.0/10 based on user reviews.

Luxury Escapes: The World's Best Holidays is classified as Documentary.